What is __vector(4) long long int? This is pretty low level stuff, and I'm not too familiar with this. Similarly, SystemVerilog casting means the conversion of one data type to another datatype. This is pretty low level stuff, and I'm not too familiar with this. Mycode: recordeddataR = long (values [1]); I think I need to convert my values [1] to a char string and use "atol" but I don't know how. The value is boxed, and then when I try to cast it to T (which is Int32), I get an InvalidCastException. static_cast in C++ | Type Casting operators - GeeksforGeeks cannot dynamic_cast 't' (of type 'void*') to type 'struct mom::object*' (source is not a pointer to class) 5 posts views Thread by verec | last post: by C / C++. Table of Contents Could you give me a hint as to why this does not work? array [0].u2.iS = static_cast<iS> (1); But actually, it looks like you have provided the definition for an enum type (enum {details.} Ganon you have mistaken a type name for an unnamed enum, in fact the exact reverse of what you postulate has happened, i.e. c++ - Invalid conversion from void* to char* [SOLVED] | DaniWeb " static_cast " operator doesn't do any runtime checks. Convert this variant to type QMetaType::UnknownType and free up any resources used. This doesn't work because you are trying to dereference a void pointer (illegal), and cast the result. cast from void* to int - C / C++ I can't just change myBytes to type char, can I? So, when you cast a (void*) to (long), you are losing 32 bits of data in the conversion. What is __vector(4) long long int? Answer (1 of 3): > Can we typecast void into int? 'this' is a constant pointer to a constant object, thus compiler doesn't allow to change the data members through 'this' pointer.
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